Finite Math Examples

6 P 2

${}_{6}P_{2}$

Step 1

Evaluate

6 P 2

${}_{6}P_{2}$ using the formula

n P r = \frac{n!}{(n - r)!}

${}_{n}P_{r} = \frac{n!}{(n - r)!}$ .

\frac{6!}{(6 - 2)!}

$\frac{6!}{(6 - 2)!}$

Step 2

Subtract

2

$2$ from

6

$6$ .

\frac{6!}{(4)!}

$\frac{6!}{(4)!}$

Step 3

Simplify

\frac{6!}{(4)!}

$\frac{6!}{(4)!}$ .

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Step 3.1

Rewrite

6!

$6!$ as

6 \cdot 5 \cdot 4!

$6 \cdot 5 \cdot 4!$ .

\frac{6 \cdot 5 \cdot 4!}{(4)!}

$\frac{6 \cdot 5 \cdot 4!}{(4)!}$

Step 3.2

Cancel the common factor of

4!

$4!$ .

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Step 3.2.1

Cancel the common factor.

$\frac{6 \cdot 5 \cdot 4!}{(4)!}$

Step 3.2.2

Divide

$6 \cdot 5$ by

$1$ .

$6 \cdot 5$

$6 \cdot 5$

Step 3.3

Multiply

$6$ by

$5$ .

$30$

$30$

${}_{6}P_{2}$

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$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$